2010-07-28 00:59:18 +02:00
|
|
|
/*
|
|
|
|
|
String replace()
|
|
|
|
|
|
|
|
|
|
Examples of how to replace characters or substrings of a string
|
|
|
|
|
|
|
|
|
|
created 27 July 2010
|
|
|
|
|
by Tom Igoe
|
|
|
|
|
|
2010-08-11 23:56:28 +02:00
|
|
|
http://arduino.cc/en/Tutorial/StringReplace
|
|
|
|
|
|
2010-07-28 00:59:18 +02:00
|
|
|
This example code is in the public domain.
|
|
|
|
|
*/
|
|
|
|
|
|
|
|
|
|
void setup() {
|
|
|
|
|
Serial.begin(9600);
|
|
|
|
|
Serial.println("\n\nString replace:");
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
void loop() {
|
|
|
|
|
String stringOne = "<html><head><body>";
|
|
|
|
|
Serial.println(stringOne);
|
|
|
|
|
// replace() changes all instances of one substring with another:
|
|
|
|
|
String stringTwo = stringOne.replace("<", "</");
|
|
|
|
|
Serial.println(stringTwo);
|
|
|
|
|
|
|
|
|
|
// you can also use replace() on single characters:
|
|
|
|
|
String normalString = "bookkeeper";
|
|
|
|
|
Serial.println("normal: " + normalString);
|
|
|
|
|
String leetString = normalString.replace('o', '0');
|
|
|
|
|
leetString = leetString.replace('e', '3');
|
|
|
|
|
Serial.println("l33tspeak: " + leetString);
|
|
|
|
|
|
|
|
|
|
// do nothing while true:
|
|
|
|
|
while(true);
|
2010-08-01 16:29:01 +02:00
|
|
|
}
|
