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Code Issues Releases Activity

fixing / improving printFloat() from Mikal Hart

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This commit is contained in:
David A. Mellis 2009-01-25 15:44:17 +00:00
parent 473cf103b8
commit 854c69dfde
1 changed files with 32 additions and 15 deletions
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47
hardware/cores/arduino/Print.cpp
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@ -81,7 +81,7 @@ void Print::print(long n, int base)
void Print::print(double n)
{
printFloat(n*100, 2);
printFloat(n, 2);
}
void Print::println(void)
@ -167,20 +167,37 @@ void Print::printNumber(unsigned long n, uint8_t base)
'A' + buf[i - 1] - 10));
}
void Print::printFloat(double number, uint8_t scale)
void Print::printFloat(double number, uint8_t digits)
{
double mult = pow(10,scale);
double rounded = floor(number /mult);
double biground = rounded * mult;
double remainder = (number - biground);
remainder = remainder / mult;
print(long(rounded));
print(".");
// Handle negative numbers
if (number < 0.0)
{
print('-');
number = -number;
}
while (scale--) {
double toPrint = floor(remainder * 10);
print(int(toPrint));
remainder -= (toPrint/10);
remainder *= 10;
// Round correctly so that print(1.999, 2) prints as "2.00"
double rounding = 0.5;
for (uint8_t i=0; i<digits; ++i)
rounding /= 10.0;
number += rounding;
// Extract the integer part of the number and print it
unsigned long int_part = (unsigned long)number;
double remainder = number - (double)int_part;
print(int_part);
// Print the decimal point, but only if there are digits beyond
if (digits > 0)
print(".");
// Extract digits from the remainder one at a time
while (digits-- > 0)
{
remainder *= 10.0;
int toPrint = int(remainder);
print(toPrint);
remainder -= toPrint;
}
}
}