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185 lines
6.8 KiB
Java
185 lines
6.8 KiB
Java
/*
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* TextUtilities.java - Utility functions used by the text area classes
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* Copyright (C) 1999 Slava Pestov
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*
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* You may use and modify this package for any purpose. Redistribution is
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* permitted, in both source and binary form, provided that this notice
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* remains intact in all source distributions of this package.
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*/
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package processing.app.syntax;
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import javax.swing.text.*;
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/**
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* Class with several utility functions used by the text area component.
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* @author Slava Pestov
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* @version $Id$
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*/
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public class TextUtilities
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{
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/**
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* Returns the offset of the bracket matching the one at the
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* specified offset of the document, or -1 if the bracket is
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* unmatched (or if the character is not a bracket).
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* @param doc The document
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* @param offset The offset
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* @exception BadLocationException If an out-of-bounds access
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* was attempted on the document text
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*/
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public static int findMatchingBracket(Document doc, int offset)
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throws BadLocationException
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{
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if(doc.getLength() == 0)
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return -1;
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char c = doc.getText(offset,1).charAt(0);
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char cprime; // c` - corresponding character
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boolean direction; // true = back, false = forward
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switch(c)
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{
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case '(': cprime = ')'; direction = false; break;
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case ')': cprime = '('; direction = true; break;
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case '[': cprime = ']'; direction = false; break;
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case ']': cprime = '['; direction = true; break;
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case '{': cprime = '}'; direction = false; break;
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case '}': cprime = '{'; direction = true; break;
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default: return -1;
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}
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int count;
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// How to merge these two cases is left as an exercise
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// for the reader.
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// Go back or forward
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if(direction)
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{
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// Count is 1 initially because we have already
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// `found' one closing bracket
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count = 1;
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// Get text[0,offset-1];
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String text = doc.getText(0,offset);
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// Scan backwards
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for(int i = offset - 1; i >= 0; i--)
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{
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// If text[i] == c, we have found another
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// closing bracket, therefore we will need
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// two opening brackets to complete the
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// match.
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char x = text.charAt(i);
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if(x == c)
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count++;
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// If text[i] == cprime, we have found a
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// opening bracket, so we return i if
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// --count == 0
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else if(x == cprime)
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{
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if(--count == 0)
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return i;
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}
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}
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}
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else
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{
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// Count is 1 initially because we have already
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// `found' one opening bracket
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count = 1;
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// So we don't have to + 1 in every loop
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offset++;
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// Number of characters to check
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int len = doc.getLength() - offset;
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// Get text[offset+1,len];
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String text = doc.getText(offset,len);
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// Scan forwards
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for(int i = 0; i < len; i++)
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{
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// If text[i] == c, we have found another
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// opening bracket, therefore we will need
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// two closing brackets to complete the
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// match.
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char x = text.charAt(i);
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if(x == c)
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count++;
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// If text[i] == cprime, we have found an
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// closing bracket, so we return i if
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// --count == 0
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else if(x == cprime)
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{
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if(--count == 0)
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return i + offset;
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}
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}
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}
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// Nothing found
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return -1;
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}
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/**
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* Locates the start of the word at the specified position.
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* @param line The text
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* @param pos The position
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*/
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public static int findWordStart(String line, int pos, String noWordSep)
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{
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char ch = line.charAt(pos - 1);
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if(noWordSep == null)
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noWordSep = "";
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boolean selectNoLetter = (!Character.isLetterOrDigit(ch)
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&& noWordSep.indexOf(ch) == -1);
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int wordStart = 0;
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for(int i = pos - 1; i >= 0; i--)
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{
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ch = line.charAt(i);
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if(selectNoLetter ^ (!Character.isLetterOrDigit(ch) &&
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noWordSep.indexOf(ch) == -1))
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{
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wordStart = i + 1;
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break;
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}
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}
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return wordStart;
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}
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/**
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* Locates the end of the word at the specified position.
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* @param line The text
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* @param pos The position
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*/
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public static int findWordEnd(String line, int pos, String noWordSep)
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{
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char ch = line.charAt(pos);
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if(noWordSep == null)
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noWordSep = "";
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boolean selectNoLetter = (!Character.isLetterOrDigit(ch)
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&& noWordSep.indexOf(ch) == -1);
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int wordEnd = line.length();
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for(int i = pos; i < line.length(); i++)
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{
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ch = line.charAt(i);
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if(selectNoLetter ^ (!Character.isLetterOrDigit(ch) &&
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noWordSep.indexOf(ch) == -1))
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{
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wordEnd = i;
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break;
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}
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}
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return wordEnd;
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}
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}
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