Fix: Calculating the width of a table can be incorrect when the calculation table is hidden due to an issue with jQuery's

width/outerWidth calculation (http://bugs.jquery.com/ticket/9945). This is a bit of a work around to get the css value and check if it is
a percentage - this is not perfect (since other relative values aren't checked - although they are generally unlikely to be used), but it
is effective for most cases.

media/js/jquery.dataTables.js

@@ -1,6 +1,6 @@
 /*
  * File:        jquery.dataTables.js
- * Version:     1.8.2
+ * Version:     1.8.3.dev
  * Description: Paginate, search and sort HTML tables
  * Author:      Allan Jardine (www.sprymedia.co.uk)
  * Created:     28/3/2008
@@ -67,7 +67,7 @@
 	 * Notes:    Allowed format is a.b.c.d.e where:
 	 *   a:int, b:int, c:int, d:string(dev|beta), e:int. d and e are optional
 	 */
-	_oExt.sVersion = "1.8.2";
+	_oExt.sVersion = "1.8.3.dev";
 	
 	/*
 	 * Variable: sErrMode
@@ -5764,7 +5764,9 @@
 					}
 				}
 				
-				oSettings.nTable.style.width = _fnStringToCss( $(nCalcTmp).outerWidth() );
+				var cssWidth = $(nCalcTmp).css('width');
+				oSettings.nTable.style.width = (cssWidth.indexOf('%') !== -1) ?
+				    cssWidth : _fnStringToCss( $(nCalcTmp).outerWidth() );
 				nCalcTmp.parentNode.removeChild( nCalcTmp );
 			}
 		}